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By simply applying their technique, we can transformQIPto the following mixed integer programming (MIP) prob-lem: MIP: min : X ( p;q ) 2 f N 2 w pq ˆ X i2H c pi x pi + X i2H X j2H c ij y piqj + X j2H c jq x qj! + ...
... LMN*8O;P'()JF451 6789:;<Q R=>?@:;< A E.P'()JF4516789:;<Q=>?@:;<QABCDEFGH IJKLMN* S@FTUV'WXYZ['D\] ^MN_:* S@FC'a9.bcdN'\ef ghi'C'Jf@jkdYlam JKnMN_:*op<C'Jq r;8stJFuvJwxy\zl {M_:* |}g^ S@e~Ja9KL ...
D2 ZY\YHX^]U 613 <x/F^ZYQ/BK>/J^]c@_YS``^]/=[QSZRU__c/JQ\`b]W/M^TQV^]U E^a^_^[Q]q~|kI 4 fs HU+h x: nV HKoCHO; 08\: MiYf O Gf 2ek 41 >~XGCWvQ 3t/ 51 V8=|0_fG<; 8; B 2t/f^Q 3 hVgy 82b8BMoJk ...
... 1: 100<=/7 4J7]^ _ Z[<=+8) +Z[100Z["8Q(*7 'aO5 bJO+cd6efgh ij+klm ij n ijopq "rs01+tu ev+PZ[+opq QbEwx5 =*7E 100Z[8+PNQ+>my z{7|5+&}O= ~^5=*7)*(&+,-.+PNQRS =>?@+ABO+ + }"F(*7 4O5ÄÅ Ç+'JQ É+8}O<Q(*7 * ...
j=. c #&(jq&}.) in. if. #j do. 'j0 j1'=. ({.;}.)j. if. j0 ~: jq do.A=. A E0 jq,j0 end. for_q. j1 do.A=. A E1 jq,q end. jq=. jq+1[kj=: kj,k,jq
Then the single allocation problem is formulated as follows: QIP: min : X ( p;q ) 2 f N 2 w pq X i2H c pi x pi + X i2H X j2H c ij x pi x qj + X j2H c jq x qj! + X ( p;j ) 2N£H w pj X i2H ( c pi + c ij) x pi + X ( i ...
... LMN*8O;P'()JF451 6789:;<Q R=>?@:;< A E.P'()JF4516789:;<Q=>?@:;<QABCDEFGH IJKLMN* S@FTUV'WXYZ['D\] ^MN_:* S@FC'a9.bcdN'\ef ghi'C'Jf@jkdYlam JKnMN_:*op<C'Jq r;8stJFuvJwxy\zl {M_:* |}g^ S ...
... 1: 100<=/7 4J7]^ _ Z[<=+8) +Z[100Z["8Q(*7 'aO5 bJO+cd6efgh ij+klm ij n ijopq "rs01+tu ev+PZ[+opq QbEwx5 =*7E 100Z[8+PNQ+>my z{7|5+&}O= ~^5=*7)*(&+,-.+PNQRS =>?@+ABO+ + }"F(*7 4O5ÄÅ Ç+'JQ É ...
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