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let qq(pp)=qq(pp)+1 if qq(pp)=lim+1 then let qq(pp)=1 if qq(pp)=lim*2+1 then let qq(pp)=lim+1 if qq(pp)=nn+1 then let qq(pp)=nn
22 Annex QQ, pp. 235-239, Ibid. 23 pp- 60-62, Rollo. 24 Acting Director, NBI vs. Caluag, 2 SCRA 536 (1961); Bairan vs. Tan Sui Lay, l8 SCRA 1235 (1966): De la Cruz vs. Paras, 69 ...
DD xx y hx h h Where the operators D x and 2 D x are given by 1 1 () n pp p p Dx h x hhx 22 2 2 11 1, 1 () () () nn n pp p q pp qq pp q pq Dx x x h ...
W ˆ u c f E a b E Z c w E E I?tp?O?RH‚?JGp?N?P?GHI?n?nIA?Q?JGp?O?QK?O?P?O?RN?Or?pA?} ‰ j u u c w Z U Z w] a {| E f Y U E E f f U‹ c Š _ U V V h F i C c c C g E c ` ƒ?GH?qQ?Pp?MH?O?QA?MHK?O?RNI?
... u6?? {¼?? ?81m *' pvv pwt ruq prt u6?? {¼?? ?82m *' sro srv wuv qxt u6?? {¼?? ?84m *' pwt pwo rut pqr u6?? {¼?? ?85m *' qtx qsw tov puv —' ptkvpt pukpvp rpkwwu ppktov g}**/? qq}*? pp£'? ro¡ž ...
if qq(pp)=lim+1 then let qq(pp)=1 if qq(pp)=lim*2+1 then let qq(pp)=lim+1 if qq(pp)=nn+1 then let qq(pp)=nn
... of Bernstein basis (Piegl and Tiller, 1997) we obtain 11 1 (1)() () (), 0, 1, ..., 1; iiii i i in ++ + = = ppqp q p that is, 00 (), 1, 2, ..., . ii in =+= qq pp (12) ...
... Univ SCI 2004 5(5):618-628 620 2 12 3 0 cc c ++= (7) where T2 T 1T T 2T 2T T2 2 2 T 3 2() 2 () () c c cl =+ =++ =+ ++ pp qq pp g qq pg pg ...
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