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[H 3 O +] = K a [CH 3 COOH] / [CH 3 COO-] [OH-] = K b [NH 3] / [NH 4 +] pH = pK a + log [CH 3 COO-] / [CH 3 COH] pOH = pK b + log [NH 4 +] / [NH 3]
Similarly pOH = pK b + p[A- ] 2 . Example ; The weak acid HA is o.1%ionized in a 0.2Msolution . a)what is the equilibrium constant ...
... 6258 4855(H) / 6278 3383(O) / 9817 2500(HP) Ng Hee Seang, PBM Contact No Thomson Constituency / Community Club 6254 9943 6250 2283 Name Contact No Mr Sng Jin Poh, PK, PBM, PBS 9862 ...
... Version 1 Page 7 of 7 Equations and Physical Constants K p = K (RT) n PV=nRT K a K b = K w =1.0x10-14 pH= -log[H +] pOH= -log[OH-] pH + pOH = 14 pK a = -logK a pH = pK+ log [A] [HA] a-pOH = pK ...
Similarly pOH = pK b + p[A- ] 2 . Example ; The weak acid HA is o.1%ionized in a 0.2Msolution . a)what is the equilibrium ...
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