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simplify it further using de morgan theorem? ... Put it in a Karnough map and you'll see that it is already a minimal sum-of-products.
i need the solution.. answer is yz'+x'z ... There are currently no comments for this question. * You must be logged into Answers to add comments.
... z ' + yz )' = x ' + ( y ' z ')'( yz )' = x ' + ( y + z )( y '+ z ') A simpler procedure for deriving the complement of a function is to take the dual of the function and complement ...
... z + yz 2 + y 9 + ty 5 zt 2 − 4 * =0 S 28 x 2 z + yz 2 + xy 7 S 29 x 2 z + yz 2 + y 10 U ∗ 20 x 3 + xz 2 + y 6 + rx 2 y 2 + sy 2 z 2 + txy 2 z Δ( r, s, t ) * =0 U 24 x 3 + xz 2 + y 7 V ∗ 1 23 x 2 z + yz 3 + y 6 V ∗ 1 24 x 2 ...
= x’ + (y’z’ + yz)’ [ because (xy)’ = x’ + y’ ] = x’ + (y’z’)’ (yz)’ [ because (x + y)’ = x’ y’ ] = x’ + (y + z)(y’ + z’) [ because ...
(a) x'z' + y'z' + yz' + xy (b) AC' + B'D + A'CD + ABCD (c) (A' + B' + D')(A + B' + C')(A' + B + D') (B + C' + D') 3-20 Draw the multiple-level NAND circuit for the ...
... z + yz 2 + y 9 + ty 5 zt 2 4 * =0 S 28 x 2 z + yz 2 + xy 7 S 29 x 2 z + yz 2 + y 10 U 20 x 3 + xz 2 + y 6 + rx 2 y 2 + sy 2 z 2 + txy 2 z ( r, s, t ) * =0 U 24 x 3 + xz 2 + y 7 V 1 23 x 2 z + yz 3 + y 6 ...
= x + (yz + yz) [ because (xy) = x + y ] = x + (yz) (yz) [ because (x + y) = x y ] = x + (y + z)(y + z ...
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